### 5.38.22 Remove elements of a list : remove

remove takes as argument : a boolean function f and a list L.
remove removes in the list L, the elements c such that f(c)==true.
Input :

remove(x->(x>=2),[0,1,2,3,1,5])

Output :

[0,1,1]

Remark The same applies on strings, for example, to remove all the "a" of a string:
Input :

ord("a")

Output :

97

Input :

    f(chn):={
      local l:=length(chn)-1;
      return remove(x->(ord(x)==97),seq(chn[k],k,0,l));
    }

Then, input :

f("abracadabra")

Output :

["b","r","c","d","b","r"]

To get a string, input :

char(ord(["b","r","c","d","b","r"])

Output :

"brcdbr"